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Fix & make linux conditionals uniform (#4278)

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The source used a hodge-podge of different combinations of different
macros to check for linux: 'linux', '__linux', '__linux__'.

As '__linux__' is standard (Posix), and the others are not, the source
now uniformly uses __linux__. If either linux or __linux are defined,
it is made sure that __linux__ is defined as well.
This commit is contained in:
Rogier-5 2016-07-04 21:00:57 +02:00 • committed by est31
parent f649147080
commit 1dfd977ec4
5 changed files with 14 additions and 10 deletions
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8
src/porting.h
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@ -60,7 +60,11 @@ with this program; if not, write to the Free Software Foundation, Inc.,
#include <unistd.h>
#include <stdint.h> //for uintptr_t
#if (defined(linux) || defined(__linux) || defined(__GNU__)) && !defined(_GNU_SOURCE)
// Use standard Posix macro for Linux
#if (defined(linux) || defined(__linux)) && !defined(__linux__)
#define __linux__
#endif
#if (defined(__linux__) || defined(__GNU__)) && !defined(_GNU_SOURCE)
#define _GNU_SOURCE
#endif
@ -321,7 +325,7 @@ inline const char *getPlatformName()
return
#if defined(ANDROID)
"Android"
#elif defined(linux) || defined(__linux) || defined(__linux__)
#elif defined(__linux__)
"Linux"
#elif defined(_WIN32) || defined(_WIN64)
"Windows"