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Fix & make linux conditionals uniform (#4278)

The source used a hodge-podge of different combinations of different
macros to check for linux: 'linux', '__linux', '__linux__'.

As '__linux__' is standard (Posix), and the others are not, the source
now uniformly uses __linux__. If either linux or __linux are defined,
it is made sure that __linux__ is defined as well.
This commit is contained in:
Rogier-5 2016-07-04 21:00:57 +02:00 committed by est31
parent f649147080
commit 1dfd977ec4
5 changed files with 14 additions and 10 deletions

View file

@ -630,7 +630,7 @@ bool GUIChatConsole::OnEvent(const SEvent& event)
}
else if(event.KeyInput.Char != 0 && !event.KeyInput.Control)
{
#if (defined(linux) || defined(__linux))
#if (defined(__linux__))
wchar_t wc = L'_';
mbtowc( &wc, (char *) &event.KeyInput.Char, sizeof(event.KeyInput.Char) );
prompt.input(wc);